According to Zimmels (1983), the sizes of particles used in sedimentation experiments often have a uniform distribution. In sedimentation involving mixtures of particles of various sizes, the larger particles hinder the movements of the smaller ones. Thus, it is important to study both the mean and the variance of particle sizes. Suppose that spherical particles have diameters that are uniformly distributed between 0.02 and 0.08 centimeters. Find the mean and variance of the volumes of these particles. (Recall that the volume of a sphere is (4/3) πr3) Round your answers to four decimal places. E(Y)= ___ x10−5 cm3
V(Y) = ___ x10−9

The expected value of a normal distribution is the mean of the distribution, while the variance measures the squared deviation of a value from the expected value. The expected value and the variance are: and

Given that, the diameters are:

The radius is:

So, we have:

The volume of the sphere is:

For , the volume is:

For , the volume is

The mean of a uniform distribution is:

In this case, the mean is:

So, we have:

Approximate

The variance of a uniform distribution is:

In this case, the volume is:

So, we have:

Rewrite as:

Hence, the expected value and the variance of the sphere are: and

Learn more about expected values and variance at:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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