A recipe for eight flapjacks needs 2oz of butter, 3oz of sugar, and 4 oz of rolled oats. How many flapjacks can I make if I have 14 oz of butter, 15 oz of sugar, and 16 oz of rolled oats?

Step-by-step explanation:

Eight flapjacks

2oz of butter

3oz of sugar

4 oz of rolled oats.

Each flapjack

Butter = 2/8 = 1/4 oz

Sugar = 3/8 oz

Rolled oats = 4/8 = 1/2 oz

How many flapjacks can I make if I have

14 oz of butter,

15 oz of sugar, and

16 oz of rolled oats?

Butter

= 14 oz ÷ 1/8 oz

= 14 × 8/1

= 112 flapjack

Sugar

= 15 oz ÷ 3/8 oz

= 15 × 8/3

= 120/3

= 40 flapjacks

Rolled oats

16 oz ÷ 1/2 oz

= 16 × 2/1

= 32 flapjack

Therefore,

Considering the quantity of rolled oats available, the number of flapjacks that could be made is 32

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.