Identify the equation of the circle that has its center at (7, -24) and passes through the origin.

(x-7)²+(y+24)² = 625

Step-by-step explanation:

A circle with center (h, k) and radius r can be represented as

(x-h)²+(y-k)² = r²

We know the center and one point, and need to find the radius. The radius is equal to the distance from the center to any point on the circle. Therefore, we need to find the distance from the center to the point on the circle (in this case, the origin) to obtain the radius.

The distance formula for points (x₁, y₁) and (x₂, y₂) is √((x₁-x₂)²+(y₁-y₂)²). Note that x₁ and x₂ (as well as y₁ and y₂) are interchangeable but x₁ and y₁ or x₂ and y₂ are not.

Our distance between (7, -24) and the origin is

√((x₁-x₂)²+(y₁-y₂)²) = √((7-0)²+(-24-0)²)

= √625

= 25

Therefore, the radius is 25 and our equation is

(x-7)²+(y-(-24))² = (x-7)²+(y+24)² = 25² = 625

i hope this is what you were looking for.

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step-by-step explanation: