Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'. 1. Describe the transformation using words. Make sure you refer to the characteristics and the coordinates.
2. Draw a line segment from point S to the reflecting line, and then draw a line segment from point S' to the reflecting line. What do you notice
about the two line segments you drew? Do you think you would notice the same characteristics if you drew the line segment connecting T
with the reflecting line and then t' with the reflecting line? How do you know?

The x-coordinates of will be the negation of the x-coordinates of

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for and

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of are

Refer to attachment for illustrations

(1) Reflect over y-axis and describe the transformation

To reflect across the y-axis, the following rule must be followed

This means that:

The description of the transformation is as follows:

Notice that the signs of the x-coordinates and of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

(2) Compare the segments and the line of reflection

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

The distance between S' and the y-axis is:

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

From T and T' to the y-axis is:

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the answer is 62