Using Eulers formula, how many edges does a polyhedron with 6 faces and 6 vertices have? Eulers Formula: F+V=E+2

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4

Ithink the answer is b i hope it my friend message me if i’m wrong and i’ll change my answer and fix it for you