Consider the function f(x) = log2 (x) Write the transformation equation (x, y) → (...) that gives the following features:
i. Horizontal scaling of %
ii. Vertical reflection
iii. Vertical asymptote located at x = -2
b. What is the expression for the transformed function?
c. Transform the base points (1, 0), (6, 1), (b?, 2), and (0, v. a) of the original function
using your answer from part a)
d. Produce a neat, to-scale sketch of the transformed graph. Include number
markings on the axis and indicate the vertical asymptote with a dotted line

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

sorry but i cant draw that

the answer is 9 because the question is telling how much it be together.