Samuel was given the diagram below and asked to prove that AC = BD. What would be the fifth step of the proof?
Given: Quadrilateral ABCD is a rectangle.
Prove: AC BD
Statements
1. Quadrilateral ABCD is a rectangle
2. AB a CD
3. ZBAD ZODA
4. ADE AD
5.
6. AC 230
Reasons
Given
Opposite sides of a rectangle are equa.
All angles of a rectande are equal.
Reflexive Property of Equality
Corresponding parts of congruent
triangles are congruent
с
A. AABD = SACD, using the SSS congruence theorem
B. ABAD = ACDA, using the SAS congruence theorem
C. 4ACB ACDA, using the SAS congruence theorem
D. ABC = ADAC, using the AAA congruence theorem
PREVIOUS

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )