The compound butanol has the following structural formula. A string of 4 C atoms are bonded above, left, and below to H. The right-hand end is bonded to O, which in turn is bonded to H. Which of these is a structural isomer of butanol? A string of 4 C atoms are bonded above, below, left and right to H. A string of 4 C atoms is bonded above, below, left, and right to H, except the second C, which is bonded below to O, which is bonded below to H. A string of 4 C atoms is bonded above, below, left, and right to H, but the chain is interrupted between the first and second C, which are bonded to an O between them. A string of 4 C atoms is bonded above, below, and left to H, except the last C has no H below and is double-bonded to an O to the right.

Option B

Explanation:

A structural isomer of an organic compound refers to a compound that has the same molecular formula, but a different arrangement of atoms in the carbon chain.

Butanol has the molecular formula C4H9OH.  We can now explore the options to see if any of them have the same molecular formula.

Option A has no oxygen in it, so we can rule it out

Option B has 4 carbon atoms, 9 hydrogen atoms and 1 oxygen atom as well as single Chain branches. This makes it the structural isomer of Butanol ( C4H9OH).

Option C has only 3 carbon atoms which rules it out as being an isomer.

Step-by-step explanation:

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

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step-by-step explanation: