Solve : Sin 2theta-cos3theta=0​

theta = + 2n, + 2n, + 2n, + 2n

Step-by-step explanation:

sin^2 theta - cos^3 theta = 1

cos^3 theta = 1 - sin^2 theta

sin^2 theta - cos^3 theta = 0

Substitute

sin^2 theta - ( 1 - sin^2 theta ) = 0

Distribute negative

sin^2 theta - 1 + sin^2 theta = 0

Combine same values

2sin^2 theta - 1 = 0

2sin^2 theta = 1

sin^2 theta =

sin theta = +-

Right Triangle:  1 - 1 -

theta = + 2n, + 2n, + 2n, + 2n

period of Sin function is 2

i dont know the answer but here's a picture of a dog

we would need a picture of the quadrilateral in order to answer the question. also, it seems that the question is missing some components.