Find the missing side lengths. Leave your answers as radicals in simplest form.

Step-by-step explanation:

For the question 1:

The given is a special right triangle with angle measures of

90-60-30 and side lengths represented by :

a - a and 2a

The side length that sees 90 degrees is represented with a

The side length that sees 60 degrees is represented with a

The side length that sees 30 degrees is represented with 2a

Here the side length that sees angle measure 60 is given as

so a =   to find the value of a we divide   with

=

so y = and x = 2

for second question

the square value of hypotenuse is equal to sum of other two side length's square value

10^2 + 6^2 = x^2

100 + 36 = x^2

136 = x^2

= x

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6