Please hurry I will mark you brainliest What is the equation of the line parallel to y = 2x - 4 and with the same x - intercept as 3x – 4y = 12?

y=2x-8

Step-by-step explanation:

Hi there!

We want to find an equation of the line parallel to y=2x-4 but has the same x intercept as 3x-4y=12

Parallel lines have the same slope, but different y intercepts

In y=2x-4, which is written in y=mx+b form, m is the slope and b is the y intercept

2 is in the place of where the slope would be, so the slope of that line is 2

That means the slope of the line parallel to it would also have a slope of 2

Here is the equation of the parallel line so far:

y=2x+b

We need to find b, the y intercept

Typically, we'll substitute a point into the equation to solve for b, but we don't have a point, yet

We're given that the new line has the same x intercept as 3x-4y=12

The x intercept is the point where the line passes through the x axis, and so the value of y at that point is 0

Let's substitute 0 for y in 3x-4y=12 and solve for x to find the x intercept

3x-4(0)=12

Multiply

3x=12

Divide both sides by 3

x=4

So the value of the x intercept is 4. As a point, it's (4,0)

So now substitute the values of the point (4,0) into y=2x+b to find b

0=2(4)+b

Multiply

0=8+b

Subtract 8 from both sides

-8=b

Substitute -8 as b into the equation

y=2x-8

Hope this helps!