Resolve 3x-1÷(x+1)^2 into partial fraction
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  3/(x +1) -4/(x +1)^2

Step-by-step explanation:

The partial fraction expansion will be of the form ...

  A/(x+1)^2 +B/(x+1)

We can find the values of A and B by writing the sum of these terms:

  = (A +B(x +1))/(x +1)^2

Then we require ...

  B = 3

  A +B = -1   ⇒   A = -4

So, the desired expansion is ...

  3/(x +1) -4/(x +1)^2

yo

step-by-step explanation:

yo

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions