The diagram above shows a plan for a park. ABCD is a rectangle. APB and DQC are semicircles centred at X and Y.
Given AB = 7 cm and AC = 25 cm.
Calculate the perimeter of the park in cm.​

Perimeter of the park = 70 cm

Step-by-step explanation:

Perimeter of the park = perimeter of the 2 semicircles + 2(length of the rectangle)

Perimeter = 2πr + 2(BC)

✔️Perimeter of the 2 semicircles = 2πr

Where,

radius (r) = ½(AB) = ½(7)

r = 3.5 cm

Perimeter = 2*π*3.5 = 7*π

Perimeter of the two semicircles = 21.9911486 ≈ 22 cm

✔️Find BC using Pythagorean theorem:

Thus,

BC = √(AC² - AB²)

AC = 25

AB = 7

BC = √(25² - 7²) = √576

BC = 24

✔️Perimeter of the park = perimeter of the 2 semicircles + 2(length of the rectangle)

Perimeter of the park = 22 + 2(24)

= 22 + 48

= 70 cm

let soccer = x and golf = y

part a

1st equation: x + y = 125

2nd equation: x = y +45

part b

replace x in the 1st equation with the 2nd one:

y + 45 + y = 125

simplify:

2y + 45 = 125

subtract 45 from each side:

2y = 80

divide both sides by 2:

y = 80/2

y = 40

she plays golf for 40 minutes.

part c

no because she plays soccer for 45 minutes longer than golf 40 +45 =   85 minutes, not 80 minutes.

your answer would be 10x - 1