We want to find the zeros of this polynomial: p(x) = 2x^3 + 3x^2 - 18x -27.

Plot all the zeros (x-intercepts) of the polynomial in the graph.

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 - 18x -27

p(x) = x^2(2x+3) -9(2x+3)

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.

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