Find f′ in terms of g′ f(x)=x2g(x)

Select one:

f′(x)=2xf′(x)+2xg′(x)

f′(x)=2xg′(x)

f′(x)=2x+g′(x)

f′(x)=x2g(x)+2x2g′(x)

f′(x)=2xg(x)+x2g′(x)

9514 1404 393

  (e) f′(x)=2xg(x)+x²g′(x)

Step-by-step explanation:

The product rule applies.

  (uv)' = u'v +uv'

__

Here, we have u=x² and v=g(x). Then u'=2x and v'=g'(x).

  f(x) = x²·g(x)

  f'(x) = 2x·g(x) +x²·g'(x)

a = 11 : 4

b = 38

c = 1 for every 6

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.