A taxi ride cost $2 for the first 1/5 of a km and 40 cents for each additional fifth of a km. Dan has $9.60. What is the longest taxi ride he can afford, in kilometres?

4 kilometers

Step-by-step explanation:

First! Let's create an equation, with our variable (x) representing the number of additional fifth kilometers Dan can afford.

2 + 0.40x = 9.60

Now, we have to solve for our x value by subtracting 2 from both sides.

0.40x = 7.60

Next, we can divide both sides by 0.40 to find out what our x value is equal too.

x = 19

Don't forget this x value is just for the number of additional fifth kilometers Dan can afford on top of his first fifth mile.

So! Dan can afford 20 fifth kilometers, which in turn in is 4 kilometers in total.

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-SGO

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3