Will give brainiest Find the perimeter of a quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1,−3). a 12 units
b 16 units
c 20 units
d 24 units

Step-by-step explanation:

First graph the coordinates so you can see where they are (hint: you can use the website desmos to graph coordinates).

Perimeter formula:

length + width + length + width

Count the distance between each line:

CD = 3

DE = 4

EF = 3

FC = 4

If you can't tell the distance between the lines (because they are diagonal, you can also calculate the distance using this equation:

Line segment = square root ((x2 - x1)^2 + (y2 - y1)^2)

CD = square root ((2 - (- 2)^2 + (4) - 1^2)

CD = square root (0^2 + 3^2)

CD = square root (0 + 9)

CD = square root (9)

CD = 3

DE = square root ((5 - (2)^2 + (0) - 4)^2)

DE = square root (0^2 + -4^2)

DE = square root (0 + 16)

DE = square root (16)

DE = 4

EF = square root ((1 - (5)^2 + (-3) - 1)^2)

EF = square root ((0^2 + - 3^2))

EF = square root (0 + 9)

EF = square root (9)

EF = 3

FC = square root (1 - (-2)^2 + (-3) - 1)^2)

FC = square root (0^2 + -4^2)

FC = square root (0 + 16l

FC = square root (16)

FC = 4

After solving for the distance between each line, plug the information into the perimeter formula:

4 + 3 + 4 + 3

7 + 7

14

When checking with your options, there is no option for 14. However, I checked my work several times and have come up with the same answer each time. Please check to make sure there is not another option for answers available and that the listed coordinates are correct. Regardless, I hope my answer helps.

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation:

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