Find the absolute maximum and absolute minimum for f (x )equals x cubed minus 2 x squared minus 4 x plus 2 on the interval 0 less or equal than x less or equal than 3.

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Step-by-step explanation:

The extrema will be at the ends of the interval or at a critical point within the interval.

The derivative of the function is ...

  f'(x) = 3x² -4x -4 = (x -2)(3x +2)

It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...

  f(0) = 2

  f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6

  f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1

The absolute maximum on the interval is f(0) = 2.

The absolute minimum on the interval is f(2) = -6.

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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