PLEASE PLEAS HEL what are the zeros in this equation?
f(x) = 2x^2 + 6x^2 + 2

So you definately wrote something wrong but I will assume the 6x^2 was meant to be just 6x.

2x^2 + 6x + 2 = 0

x^2 + 3x + 1 = 0

I can't seem to find a better way than to simply use the quadratic formula:

(-3 + sqrt(9 - 4*1*1))/2 -0.382

(-3 - sqrt(9 - 4*1*1))/2 -2.62

So the zeroes for this function are at

(-0.382, 0) and (-2.62, 0)

Or exactly:

((-3 + sqrt(9 - 4*1*1))/2, 0) and ((-3 - sqrt(9 - 4*1*1))/2, 0)

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )