The outer radius of a cylindrical metal tube is R and t is the thickness of the metal. a Show that the volume, V. of metal in a length.7 units, of the tube is given by V. = m(2R - 0). b Hence calculate V when R = 7.5.1 = 1 and l= 20​

Complete question is;

The outer radius of a cylindrical metal tube is R and t is the thickness of the metal.

A) Show that the volume, V, of metal in a length, l units, of the tube is given by V = πlt(2R - t)

B) Hence calculate V when R = 7.5. t = 1 and L = 20

A)V = πlt(2R - t)

B)V = 879.65

Step-by-step explanation:

A) Formula for volume of a hollow cylinder is; V = π(R² - r²)h

Where;

R is outer radius

r is inner radius

h is height/length of tube

Now, we are told thickness is t.

Thus; R - r = t

Also, h = l

Thus;

V = π(R² - r²)h

Let's factorize this to get;

V = π((R + r)(R - r))l

V = π((R + r))lt

Since R - r = t

Then, r = R - t

Thus;

V = π(R + R - t)lt

V = πlt(2R - t)

B) when R = 7.5, t = 1 and l= 20;

V = ​πlt(2R - t)

V = ​π × 20 × 1(2(7.5) - 1)

V = 879.65

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step-by-step explanation: