Let f(x) = 5 + 12x − x^3. Find (a) the x- coordinate of all inflection points, (b) the open intervals on which f is concave up, (c) the open intervals on which
f is concave down.

A) x = 0.

B) f is concave up for (-∞, 0).

C) f is concave down for (0, ∞).

Step-by-step explanation:

We are given the function:

A)

We want to find the x-coordinates of all inflection points.

Recall that inflections points (may) occur when the second derivative equals zero. Hence, find the second derivative. The first derivative is given by:

And the second:

Set the second derivative equal to zero:

And solve for x. Hence:

We must test the solution. In order for it to be an inflection point, the second derivative must change signs before and after. Testing x = -1:

And testing x = 1:

Since the signs change for x = 0, x = 0 is indeed an inflection point.

B)

Recall that f is concave up when f''(x) is positive, and f is concave down when f''(x) is negative.

From the testing in Part A, we know that f''(x) is positive for all values less than zero. Hence, f is concave up for all values less than zero. Our interval is:

C)

From Part A, we know that f''(x) is negative for all values greater than zero. So, f is concave down for that interval:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes