V U
T
In square QRST, points U and V are midpoints. If the square has a side length of 14.6 mm, what is the probability
that a point chosen at random in the square lies in the shaded triangle region? Round the answer to the nearest
thousandth
A. 0.034
B. 0.068
C. 0.125
D 0.548

JKLM is a square with sides of length 6 units. Points A and B are the midpoints of sides KL and ML, respectively. If a point is selected at random from the interior of the square.

We have to find the probability that the point will be chosen from the interior of △JAB.

Now,

Area of square JKLM is equal to 6

2

=36 sq.units

Now, we have

ar(△KAJ)=

2

1

×AK×KJ

=

2

1

×3×6=9sq.unit

ar(△JMB)=

2

1

×JM×BM

=

2

1

×6×3=9sq.unit

ar(△AJB)=36−9−9−

2

9

=18−

2

9

=

2

36−9

=

2

27

sq.units.

We know that probability=

Totalnumberofevent

Numberoffavourableevent

=

36

2

27

=

2×36

27

=

8

3

Hence the probability that the point will be chosen from the interior of △AJB is

8

3

hope it helps

what is

step-by-step explanation:

just pick what you think i need more time let me know if this

step-by-step explanation: