The restrictions for f(x)=2x+3/x^2−4 are ±2

True

False

 True

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Explanation:

If you meant to say , then we cannot have x^2-4 equal to 0

We can never have 0 in the denominator.

Set the expression equal to 0 and solve for x

x^2 - 4 = 0

(x-2)(x+2) = 0 .... difference of squares rule

x-2 = 0 or x+2 = 0

x = 2 or x = -2

So if either x = 2 or x = -2, then we have x^2-4 equal to zero.

So these are the values we must kick out of the domain to avoid a division by zero error.

In short, the restrictions for x are 2 and -2. That's why the statement is true.

sine

step-by-step explanation:

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .