Sue has 3 cats. Each cat eats 1 4 of a tin of cat food each day. Sue buys 4 tins of cat food. Has Sue bought enough cat food to feed her cats for 5 days? You must show how you get your answer

3 3/4 tins of food

Step-by-step explanation:

Number of cats = 3

Quantity of food for each cat per day = 1/4 of a tin

Total tins of cat food sue bought = 4 tins

Has Sue bought enough cat food to feed her cats for 5 days?

Quantity of food 3 cats eat per day = Quantity of food for each cat per day × Number of cats

= 1/4 × 3

= 3/4 of a tin

Total Quantity of food 3 cats eat for 5 days = Quantity of food 3 cats eat per day × 5 days

= 3/4 × 5

= (3 * 5) / 4

= 15/4

= 3 3/4 tins of food

Total Quantity of food 3 cats eat for 5 days = 3 3/4 tins of food

Recall,

Total tins of cat food sue bought = 4 tins

Therefore, Sue bought enough cat food to feed her cats for 5 days

idk

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.