given that the value of circumference of a circle is 2/3 of its area. determine the length of the radius of the circle!​

Let's assume the redius of the given circle is (r).

so,

According to the question,

circumference of a circle is 2/3 of its area.

Therefore, the length of the radius of the circle is 3 unit

The length of radius of circle = 3

Step-by-step explanation:

let the radius of circle be r

A.T.Q.

=> circumference = 2/3×area of circle

=> 2πr= 2/3×πr²

=> 2πr×3/2= πr²

=> 3πr= πr²

=> 3= πr²/πr

=> r = 3

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct