Find the equation of the line passing through the point (-3.6, 2.1) and parallel to the line 4.9x + 5.4y = 3

y = -4.9/5.4x - 1.17

Step-by-step explanation:

First let's convert the equation to standard form of y = mx + b.

4.9x + 5.4y = 3

Subtract 4.9x from both sides.

5.4y = -4.9x + 3

Divide each term by 5.4.

y = -4.9/5.4x + 0.56

If two lines are parallel to each other, they have the same slope slopes.

The first line is y = -4.9/5.4x + 0.56. Its slope is -4.9/5.4. A line parallel/perpendicular to this one will also have a slope of -4.9/5.4.

Plug this value (-4.9/5.4) into your standard point-slope equation of y = mx + b.

y = -4.9/5.4x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-3.6, 2.1). Plug in the x and y values into the x and y of the standard equation.

2.1 = -4.9/5.4(-3.6) + b

To find b, multiply the slope and the input of x (-3.6)

2.1 = 3.27 + b

Now, subtract 3.27 from both sides to isolate b.

-1.17 = b

Plug this into your standard equation.

y = -4.9/5.4x - 1.17

This equation is parallel/perpendicular to your given equation (y = -4.9/5.4x + 0.56) and contains point (-3.6, 2.1)

Hope this helps!

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

its 8

step-by-step explanation: