Use variation of parameters to find a general solution to the differential equation given two linearly independent solutions to the corresponding homogeneous equation ty′′+(5t−1)y′−5y=9t2e−5t, y1=5t−1,y2=e−5tty″+(5t−1)y′−5y=9t2e −5t, y1=5t−1,y2=e−5t