Find f^-1 for the function f(x)=(x-10)^3+4

f^(-1)(x)=(x-4)^(1/3)+10

Step-by-step explanation:

So to find the inverse we need to first solve the equation y=(x-10)^3+4 for x.

Subtract 4 on both sides:

y-4=(x-10)^3

Cube root (or raise both sides to 1/3 power):

(y-4)^(1/3)=x-10

Add x on both sides:

(y-4)^(1/3)+10=x

Swap x and y:

(x-4)^(1/3)+10=y

Symmetric property of equality:

y=(x-4)^(1/3)+10

So f^(-1)(x)=(x-4)^(1/3)+10.

d? maybe

step-by-step explanation:

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: