The picture below shows a box sliding down a ramp: A right triangle ABC has measure of angle ABC equal to 90 degrees and measure of angle ACB equal to 65 degrees. The length of AB is 12 feet. What is the distance, in feet, that the box has to travel to move from point A to point C? 12 divided by sec 65 degrees
12 cosec 65°
12 sin 65°
12 divided by cot 65 degrees

The Image of the triangle is missing and so i have attached it.

B: 12 cosec 65°

Step-by-step explanation:

From the diagram attached, we cans see the triangle is a right angle triangle with a given internal angle of 65° and side AB with a length of 12 ft.

Now, we can use trigonometric ratios to find the distance the box has to move from point A to point C which is basically the distance AC.

Now, the given side AB is opposite to the angle. While the required side AC is the hypotenuse.

Thus;

Opposite/hypotenuse = sin θ

Thus;

AB/AC = 12/AC = sin 65

Thus;

AC = 12/sin 65

From trigonometric relationships, we know that;

1/sin θ = Cosec θ

Thus;

AC = 12 cosec 65

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you

f(x)=4

step-by-step explanation: