Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Write a system of equations that can be used to find how many problems of each
point value are on the test.
Let x be the number of questions worth 5 points and let y be the number of questions worth 2 points.
O x + y = 29, 5x + 2y = 100
Ox+y = 100, 5x + 2y = 29
O 5x + y = 29, 2y + x = 100
O 2x + y = 100, 5y + x = 29

x + y = 29, 5x + 2y = 100

Step-by-step explanation:

First, create an equation based on how there are 29 problems on the test.

x + y represents all of the questions on the test, so it should be set equal to 29.

The first equation is x + y = 29.

Now, create an equation based on how the test is worth 100 points.

5x will represent the points from the questions worth 5 points, and 2y will represent the points from the questions worth 2 points.

These terms will be added together, and set equal to 100.

The second equation is 5x + 2y = 100.

So, the system of equations is x + y = 29, 5x + 2y = 100

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

d 600 because 15*10*2=300

300+300=600

step-by-step explanation: