Sue has 20 biscuits in a tin there are : 12 plain 5 chocolate 3 currant sue takes out two biscuits out the tin what is the probability that the two biscuits are not the same

P(2 different) ≈ 58.42%

Step-by-step explanation:

To find the probability that the 2 selected are different, we have to first find the probability that the 2 selected are the same.

probability that they are the same;

P(2 plain biscuits) = (12/20) × (11/19) = 132/380

P(2 chocolates) = (5/20) × (4/19) = 20/380

P(2 currant chocolates) = (3/20) × (2/19) = 6/380

Thus, generally;

P(2 same biscuits of either 3 types) = (132/380) + (20/380) + (6/380)

P(same) = 158/380

P(same) = 79/190

Thus, the probability that they are different will be;

P(2 different) = 1 - P(two same)

Thus;

P(2 different) = 1 − (79/190)

P(2 different) = 111/190

P(2 different) ≈ 58.42%

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

x-3y=4

step-by-step e