Identify the dependent variable: the time it takes to make rag dolls for a mission in Africa and the number of people working on the dolls the distance travelled while walking and the time taken the cost of an end of year grade 9 party and the number of people attending

The time it takes to make rag dolls for a mission in Africa.

The time taken.

The cost of an end year party.

Step-by-step explanation:

The dependent variable refers to the variable which is predicted or measured in an experiment , the value of the dependent variable relies on the variation in the independent or predictor variable.

The time it takes to make rag dolls for a mission in Africa and the number of people working on the dolls ;

DEPENDENT VARIABLE = The time it takes to make rag dolls for a mission in AFRICA. This is because time taken will depend on the number of people working.

The distance travelled while walking and the time taken ;

DEPENDENT VARIABLE = THE time taken

The time taken will depend on distance traveled.

The cost of an end of year grade 9 party and the number of people attending ;

DEPENDENT VARIABLE = The cost of an end year party.

Cost of partybwill depend on the number of people attending.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.