Use the algebraic rules for even and odd functions to classify each function as even odd or neither

Step-by-step explanation:

f(x)=-2x³+x-3

-f(x)=2x³-x+3

f(-x)=-2(-x)³+(-x)-3

=2x³-x-3

it is not equal to f(x) or -f(x)

so it is neither even or odd.

it is neither even or odd.

f(x)=x^4-x^2+10

f(-x)=(-x)^4-(-x)^2+10=x^4-x^2+10=f(x)

it is an even function.

it is an even function.

f(x)=x^9-x^5+4x^3

f(-x)=(-x)^9-(-x)^5+4(-x)^3

=-x^9+x^5-4x^3

=-(x^9-x^5+4x^3)

=-f(x)

it is an odd function.

yes

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a