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Mathematics, 11.07.2021 01:00 Shyshy876

Solve (x + 2 < 5) ∩ (x - 7 > -6). A. {all real numbers}
B. {x | 1 < x < 3}
C. {x | x < 3 or x > 1}

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Solve (x + 2 < 5) ∩ (x - 7 > -6). A. {all real numbers}
B. {x | 1 < x < 3}
...

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