2. Caveman Sampson chases a saber tooth tiger at an average speed of 3 miles per hour. The tiger runs at an average speed of 5 miles per hour, but rests for 2 hours after running for 2 hours. How long, in hours, will it take Sampson to catch the tiger if the tiger starts 2 miles in front of him and they start running at the same time? A. 7 hours B. 6 hours C. 5 hours D. 4 hours​

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  D.  4 hours

Step-by-step explanation:

The tiger will run (5 mi/h)(2 h) = 10 mi in 2 hours. That will put it 2+10 = 12 miles from Sampson's starting location.

Samson can run 12 miles in time ...

  time = distance/speed = (12 mi)/(3 mi/h) = 4 h

Sampson will get to the tiger's location after 4 hours, just as the tiger is ending its rest period.

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The graph shows the position of Sampson (red) and the tiger (blue) x hours after the chase starts. The distance (y miles) is measured from Sampson's starting point, assuming the tiger is running away.

4x and 6y

im not sure though

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.