Drag the equations to the correct locations on the table. Not all equations will be used. Determine which equation is parallel to line JK and which is perpendicular to line JK.

9514 1404 393

Step-by-step explanation:

The equation of the given line can be written as ...

  Δy·x -Δx·y = Δy·x1 -Δx·y1

where Δy and Δx are the differences in y and x coordinates of two points on the line, respectively. Here, we can find them to be ...

  Δy = 5-(-5) = 10

  Δx = -5 -1 = -6

Then the equation of the given line can be written as ...

  10x +6y = 10(-5) +6(5) = -20

Dividing by 2 puts this in standard form:

  5x +3y = -10 . . . . . . equation of the graphed line

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A parallel line will have the same x- and y-coefficients with a different constant. The equation of the parallel line is 5x +3y = 13.

A perpendicular line will have the x- and y-coefficients swapped, with one of them negated. The equation constant will likely be different. The coefficients may be multiplied by some factor so all the numbers are integers.

The equation of a perpendicular line is 6x -10y = 7.

-3.5 degrees per hour

step-by-step explanation:

find the unit rate:

-12   1/4 degrees           12.25 degrees

= - = -3.5 degrees per hour

      3   1/2 hours               3.5 hours

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10