The sum of 4 consecutive integers is 122. What is the third number in this sequence?

31

Step-by-step explanation:

Let the smallest integer be x.

Since the 4 integers are consecutive (they come right after the other),

2nd integer= x +1

3rd integer= x +1 +1= x +2

4th integer= x +2 +1= x +3

Sum of the integers= 122

x +x +1 +x +2 +x +3= 122

4x +6= 122

4x= 122 -6

4x= 116

x= 116 ÷4

x= 29

3rd number

= 29 +2

= 31