The time between surface finish problems in a galvanizing process is exponentially distributed with a mean of 41 hours. A single plant operates three galvanizing lines that are assumed to operate independently. Round your answers to four decimal places (e. g. 98.7654). (a) What is the probability that none of the lines experiences a surface finish problem in 41 hours of operation?
(b) What is the probability that all three lines experience a surface finish problem between 24 and 41 hours of operation?

a) The probability that none of the lines experiences a surface finish problem in 41 hours of operation is 0.0498.

b)The probability that all three lines experience a surface finish problem between 24 and 41 hours of operation is 0.0346.

Step-by-step explanation:

a)

b)

For 3 where, P(X=1, Y==1, Z=1)

the answer will be

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles