in an isosceles triangle two sides are equal. the third side is 2 less than twice the length of the sum of the two sides. the perimeter is 40. what are the lengths of the 3 sides

s for length of either equal side

b for the unequal side

b=-2+2*(s+s) and 2s+b=40

b=2*2s-2

b=4s-2

2s+4s-2=40

6s-2=40

6s=42

s=7

b=4*7-2

b=28-2

b=26

is there answer choices?

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: