Which function represents a reflection of f(x) = 2(0.35)x over the y-axis? h(x) = 2(0.35)x
h(x) = –2(0.35)x
h(x) = 2(0.35)–x
h(x) = 2(–0.35)–x

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

answer: #1 ads up by 8 and i don't know #2

four boxes of pizza

hope this