John finds that the sum of two numbers is 24 and their difference is one sixth of the sum. Find the smallest number between the two numbers.

Given:

The sum of two numbers is 24 and their difference is one sixth of the sum.

To find:

The smaller number between the two numbers.

Solution:

Let x and y be the two numbers where x>y.

The sum of two numbers is 24.

          ...(i)

Their difference is one sixth of the sum.

             ...(ii)

Adding (i) and (ii), we get

Putting in (i), we get

The two numbers are 14 and 10.

Therefore, the smaller number between the two numbers is 10.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this