Mathematics, 08.07.2021 17:40 Mimical

Given: ∠1 = ∠2; ∠C = ∠D Prove: CX = DX

|
1. ∠ ≅ ∠ 1 2; ∠ ≅ ∠ C D| 1. |
2. AB = AB | 2. |
3. ΔABC ≅ ΔBAD| 3. |
4. AD = BC | 4. |
5. AD = AX + DX | 5. |
6. BC = BX + CX | 6. |
7. AX + DX = BX + CX | 7. |
8. AX = BX | 8. |
If 2 ∠’s of a Δ are =, then the sides opposite them are =
9. DX = CX | 9. |
10. CX = DX | 10.

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Given: ∠1 = ∠2; ∠C = ∠D Prove: CX = DX

|
1. ∠ ≅ ∠ 1 2; ∠ ≅ ∠ C D| 1. |
...