Iliana rotated trapezoid WXYZ 180° about the origin. On a coordinate plane, trapezoid W X Y Z has points (negative 4, 2), (negative 3, 4), (negative 1, 4), (0, 2).

What is the correct set of image points for trapezoid W’X’Y’Z’?

W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
W’(4, 2), X’(3, 4), Y’(1, 4), Z’(0, 2)
W’(–2, –4), X’(–4, –3), Y’(–4, –1), Z’(–2, 0)
W’(2, 4), X’(4, 3), Y’(4, 1), Z’(2, 0)

W'(4, -2), X'(3, -4), Y'(1, -4), Z'(0, -2)

Step-by-step explanation:

The vertices of the trapezoid WXYZ are, W(-4, 2), X(-3, 4), Y(-1, 4), and Z(0, 2)

The coordinates of the image following the rotation transformation of the preimage (x, y) 180° about the origin is (-x, -y)

Therefore, following the rotation transformation of trapezoid WXYZ, the coordinates of the image W'X'Y'Z' are given as follows;

W(-4, 2) rotated 180° about the origin gives W'(4, -2)

X(-3, 4) rotated 180° about the origin gives X'(3, -4)

Y(-1, 4) rotated 180° about the origin gives Y'(1, -4)

Z(0, 2) rotated 180° about the origin gives Z'(0, -2)

Therefore, we get;

W'(4, -2), X'(3, -4), Y'(1, -4), Z'(0, -2).

Its A

Step-by-step explanation:

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