Estimate the solution to the following system of equations by graphing. 3x+5y=14
6x-4y=9

A. ( 4/3,5/2)
B. ( 7/3, -7/2 )
C. ( -5/2, -7/2)
D. (5/2, 4/3) ​

(101/42, 19/14)

Step-by-step explanation:

Given the following equations

3x+5y=14 1 * 2

6x-4y=9 ... 2 * 1

6x+10y=28

6x-4y=9  

Subtract

10y+4y = 28 - 9

14y = 19

y = 19/14

Get the value of x

Since 3x+5y = 14

3x+5(19/14) = 14

3x + 95/14 = 14

3x = 14 - 95/14

3x = 101/14

42x = 101

x = 101/42

Hence the solution is (101/42, 19/14)

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: