Mathematically verify the outlier(s) in the data set using the 1.5 rule. 7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

1. 7 & 19 are outliers.
2. 7 & 8 are outliers.
3. 7, 8, & 19 are outliers.
4. There are no outliers.

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

And

The interquartile range is:

The data values lies outside the interval are known as outliers.

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

c. (3,2,6) is the answer.

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

pls mark as brainliest