The height and base radius of a cone are increased by a factor of 2 to create a similar cone. How is the slant height of the cone affected? The slant height of the larger cone is equal to the slant height of the smaller cone. The slant height of the larger cone is double the slant height of the smaller cone. The slant height of the larger cone is 4 times the slant height of the smaller cone. The slant height of the larger cone is 8 times the slant height of the smaller cone.

The slant height of the cone affected is two times the slant height of original cone

Step-by-step explanation:

we know that

If the height and base radius of a cone are increased by a factor of  to create a similar cone

then

the scale factor is equal to  

therefore

the slant height of the cone affected is equal to the slant height of the original cone multiplied by the scale factor

Find the slant height of the original cone

Let

l> slant height of original cone

la> slant height of the cone affected

Applying the Pythagoras theorem

so

The slant height of the cone affected is two times the slant height of original cone

(I GOT THIS FROM SOMEONE ELSES ANSWER IN 2017 SO I HOPE THIS HELPS)

step-by-step explanation:

mean or average is 40.6

no because mercury has a density of 13.6 grams per centimeter squared while gold has 19.32 grams centimeter squared

step-by-step explanation: