1.the graph of y = x² is moved five units upward 2.the graph of y = 5x² is moved six units to the left
3.the graph of y = -2x² is moved seven units downward
4.the graph of y = -x² is moved two units to the left and four units downward
5.the graph of y = -3x² is moved two units to the right

I guess that we want to find the equation for each case.

First, let's define the translations:

Horizontal translation.

For a function f(x), an horizontal translation of N units is written as:

g(x) = f(x + N)

if N > 0, the translation is to the left

if N < 0, the translation is to the right.

Vertical translation:

For a function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N

if N > 0, the translation is upwards

if N < 0, the translation is downwards.

Now that we know these, we can find the equations for each case:

1. the graph of y = x² is moved five units upward

the graph is given by a vertical translation of 5 units upward.

y = x^2 + 5

2 the graph of y = 5x² is moved six units to the left

this is:

y = 5*(x + 6)^2

3: the graph of y = -2x² is moved seven units downward

this is:

y = -2x^2 - 7

4: the graph of y = -x² is moved two units to the left and four units downward

now we have two translations, first 4 units to the left and then 4 units downwards, this gives:

y = -(x + 4)^2 - 4

5: the graph of y = -3x² is moved two units to the right

Remember that to move the graph to the right, we need to have N negative, then:

y = -3(x - 2)^2

the answer is; biodiversity resulting from few ancestors

adaptive radiation occurs when a population is subjected to a large natural environment with spatial ecological variations. the parts of the population in the different ecologies begin to adapt to their local environments. due to non-random mating across the large populations, this causes the different populations from the large population to speciate within their local environments. they, therefore, diverge to different species sharing a common ancestor.  

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: