A study was conducted by a team of college students for the college research center. From the study, it was reported that most shoppers have a specific spending limit in place while shopping online. The reports indicate that men spend an average of $230 online before they decide to visit a store. If the spending limit is normally distributed and the standard deviation is $19. (a) Find the probability that a male spent at least $210 online before deciding to visit a store. Ans:
(b) Find the probability that a male spent between $240 and $300 online before deciding to visit a store. Ans:
(c) Find the probability that a male spent exactly $250 online before deciding to visit a store. Ans: (d) Ninety-one percent of the amounts spent online by a male before deciding to visit a store are less than what value? Ans:

0.8536

0.29933

Step-by-step explanation:

Given :

Mean amount spent, μ = $230

Standard deviation, σ = $19

1.)

Probability of spending atleast $210

P(x ≥ 210)

The Zscore = (x - μ) / σ = (210 - 230) / 19 = - 1.052

P(Z ≥ -1.052) = 1 - P(Z ≤ - 1.052) = 1 - 0.1464 = 0.8536

2.)

Probability that between $240 and $300 is spent:

P(x < $240) = Zscore = (240 - 230) / 19 = 0.526

P(Z < 0.526) = 0.70056

P(x < 300) = Zscore = (300 - 230) / 19 = 3.684

P(Z < 3.684) = 0.99989

P(Z < 3.684) - P(Z < 0.526)

0.99989-0.70056 = 0.29933

the answer is 16ft

step-by-step explanation:

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

happy to

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