If enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased
between 1950 and 1960, what is the expected
enrollment in 2010?

Given:

The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.

To find:

The expected enrollment in 2010.

Solution:

Percentage decrease formula:

The percentage decrease in between 1950 and 1960 is:

The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.

The expected enrollment in 2010 is:

Therefore, the expected enrollment in 2010 is 7.875 thousands.

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15