![1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\](/tpl/images/1388/8080/4256b.png)
1^2 +2^2+••••+n^2=1/6n(n+1)(2n+1)
using maths induction ...
Mathematics, 03.07.2021 21:50 smith4kaay
1^2 +2^2+••••+n^2=1/6n(n+1)(2n+1)
using maths induction
Answers: 3
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